| To: | "REALbasic Network Users Group" <realbasic-nug at lists dot realsoftware dot com> |
|---|---|
| Subject: | Re: question on md5 |
| From: | "Seth F. Duke" <seth at johnfinley dot com> |
| Date: | Fri, 27 Feb 2004 14:50:27 -0500 |
| References: | <10CC2EA3-688F-11D8-AA86-003065D606C2 at teachesme dot com> <D1413330-6942-11D8-A71D-000A95A072FC at sb dot org> <88DFEDAA-694B-11D8-9DED-003065D606C2 at teachesme dot com> <ECEE8950-6958-11D8-A71D-000A95A072FC at sb dot org> <B11FC58F-695B-11D8-9DED-003065D606C2 at teachesme dot com> |
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Create a method called something like str2hex: Function Str2Hex(src As String, sep As String) dim n, L, v as integer dim s as string L = LenB(src) for n=1 to L v = AscB(MidB(src, n, 1)) s = s + RightB("00"+Hex(v),2)+sep next return LeftB(s, LenB(s)-LenB(sep)) End Function Then you can do something like: s = Str2Hex(MD5(temp), "") To convert the raw md5 to hex I can't remember who wrote this code but I found it in the list archives. -Seth On Feb 27, 2004, at 2:32 PM, Sam DeVore wrote: doesn't hex require an integer and MD5's result is a string? |
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