Tobias,
You could sort the numbers, then compare each number to the next
number. If the two are the same, delete one. At the end of the
comparison, look at the total number of numbers and generate as many
new ones as you need. Repeat the process until you have enough.
Paul Young
On Jun 28, 2008, at 3:22 PM, tobieichner77-rb@yahoo.de wrote:
Hello,
I wrote a small app that generates six random numbers out of a range
from 1 to 70. The requirement is that no single number is used twice.
So far the only solution I came upon to prevent double entries is to
compare all entries with each other. In the case of two equal
entries, I simply re-create the random array again and do another
check.
For example:
while x(1) = x(2) or x(1) = x(3) or x(1) = x(4) or x(1) = x(5) or
x(1) = x(6) or x(2) = x(3) or x(2)= x(4) or x(2) = x(5) or x(2)=
x(6) or x(3)= x(4) or x(3) = x(5) or x(3) = x(6) or x(4) = x(5) or
x(4) = x(6) or x(5) = x(6)
for y = 1 to 6 step 1
x(y) = r.inrange(1,70)
next
wend
As you see, this leads to a long and ugly "or" chain, which will
finally end into a total mess if there are, let's say, twenty
numbers to compare with each other.
Can you give me a hint how I can manage this easier and more
convenient ?
Bye,
Tobias.
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