Re: method parameter as array

[Thomas Tempelmann <tempelmann@gmail.com>]

> Where does the array get dimensioned, in other words, at what point does
> memory get allocated?  I suppose maybe it is allocated when the array is
> dimensioned in the code that calls the method?
> And if this is the case, it sounds like that the array must be
> re-dimensioned prior to calling the method?

It gets allocated when you declare the _variable_, i.e. in:

dim a(10,10) as double

Then, when you pass this to your subroutine, only a _reference_ to
this variable is passed, just as if the array were an object. This
allows the subroutine to even modify the array (or resize it using the
"redim" statement).

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