Re: method parameter as array

[Tony Alfrey <tonyalfrey@earthlink.net>]

Thomas Tempelmann wrote:
> > Where does the array get dimensioned, in other words, at what point does
> > memory get allocated?  I suppose maybe it is allocated when the array is
> > dimensioned in the code that calls the method?
> > And if this is the case, it sounds like that the array must be
> > re-dimensioned prior to calling the method?
> It gets allocated when you declare the _variable_, i.e. in:
>
> dim a(10,10) as double
>
> Then, when you pass this to your subroutine, only a _reference_ to
> this variable is passed, just as if the array were an object. This
> allows the subroutine to even modify the array (or resize it using the
> "redim" statement).
Very powerful.  That makes it very easy to move this Fortran code to 
realBasic.  I have to change almost nothing.
Thanks



--
Tony Alfrey
tonyalfrey@earthlink.net
"I'd Rather Be Sailing"

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